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Pipe A can fill the tank 3 times faster than pipe B. If both pipes A and B running together can fill the tank in 15 minutes, then the time taken by B alone to fill the tank is:

Solution

✅ Correct Option: 3

Let Pipe B take xx minutes to fill the tank alone.

Since Pipe A is 3 times faster than Pipe B, Pipe A takes x3\frac{x}{3} minutes to fill the tank alone.


The rate of Pipe B is 1x\frac{1}{x} tank per minute.

The rate of Pipe A is 3x\frac{3}{x} tank per minute.


When both pipes work together, their rates add up:

Combined rate =1x+3x= \frac{1}{x} + \frac{3}{x}

Combined rate =4x= \frac{4}{x} tank per minute


Both pipes together fill the tank in 15 minutes, so the combined rate is 115\frac{1}{15} tank per minute.

4x=115\frac{4}{x} = \frac{1}{15}

4×15=x×14 \times 15 = x \times 1

x=60x = 60


Therefore, Pipe B alone takes 60 minutes to fill the tank.

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