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CUET Mathematics 2025 PYQs19 May Shift 1. Free, no login required.

Statistics & Applications

past year questions, CUET Mathematics 2025 19 May Shift 1

Financial Math

past year questions, Statistics & Applications, CUET Mathematics 2025 19 May Shift 1

Medium

applied

An automobile dealer wishes to buy four luxury cars of different brands given in the table below with some down payment and balance in equal monthly installments (EMI) for 10 years. The bank charges 9% interest per annum compounded monthly.

(Given0.0075×(1.0075)120(1.0075)120−1=0.01266)\left( {Given } \frac{0.0075 \times(1.0075)^{120}}{(1.0075)^{120}-1} = 0.01266\right)

Luxury CarPrice of the Car (in Rs.)Down payment (in Rs.)
P25,00,0005,00,000
Q35,00,00012,00,000
R45,00,00015,00,000
S42,00,00015,00,000

Match List-I with List-II

List-IList-II
Luxury CarEMI (in Rs.)
(A) P(I) 34,182
(B) Q(II) 37,980
(C) R(III) 29,118
(D) S(IV) 25,320

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

The EMI formula for loan repayment is:

EMI=Loan Amount×r×(1+r)n(1+r)n−1EMI = \text{Loan Amount} \times \frac{r \times (1+r)^n}{(1+r)^n - 1}

Given:

0.0075×(1.0075)120(1.0075)120−1=0.01266\frac{0.0075 \times (1.0075)^{120}}{(1.0075)^{120}-1} = 0.01266

Therefore:

EMI=Loan Amount×0.01266EMI = \text{Loan Amount} \times 0.01266

The loan amount for each car is calculated as:

Loan Amount = Price of Car - Down Payment

For Car P:

Loan Amount = 25,00,000 - 5,00,000 = 20,00,000

For Car Q:

Loan Amount = 35,00,000 - 12,00,000 = 23,00,000

For Car R:

Loan Amount = 45,00,000 - 15,00,000 = 30,00,000

For Car S:

Loan Amount = 42,00,000 - 15,00,000 = 27,00,000

For Car P:

EMI=20,00,000×0.01266EMI = 20,00,000 \times 0.01266

EMI=25,320EMI = 25,320 → (IV)

For Car Q:

EMI=23,00,000×0.01266EMI = 23,00,000 \times 0.01266

EMI=29,118EMI = 29,118 → (III)

For Car R:

EMI=30,00,000×0.01266EMI = 30,00,000 \times 0.01266

EMI=37,980EMI = 37,980 → (II)

For Car S:

EMI=27,00,000×0.01266EMI = 27,00,000 \times 0.01266

EMI=34,182EMI = 34,182 → (I)

The matching pairs are:

(A) P → (IV) 25,320

(B) Q → (III) 29,118

(C) R → (II) 37,980

(D) S → (I) 34,182

Answer: (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Related questions:

2026: 25 May Shift 1

An asset costing ₹ 1,50,000 is expected to have useful life of 5 years and scrap value of ₹ 30,000. Using linear depreciation method which of the following are TRUE?

A. Annual depreciation is ₹ 24,000

B. Depreciation rate is 20% per annum

C. Depreciation rate is 24% per annum

D. Annual depreciation is ₹ 22,000

Choose the correct answer from the options given below:

2025: 15 May Shift 1

Which of the following are correct about equated monthly installments (EMI)?

(A) The EMI depends on principal borrowed, rate of interest and tenure of the loan.

(B) It is a fixed amount made by borrower to the lender every month.

(C) The interest remains constant for every EMI in reducing balance method.

(D) As we pay off our loan, the outstanding principal amount decreases with every EMI in reducing balance method.

Choose the correct answer from the options given below:

2026: 30 May Shift 2

A bond sells at discount. Which of the following is feasible?

[YTM = yield to maturity]

2026: 30 May Shift 2

Shyamaji takes a loan of ₹20,00,000 with 10% annual interest rate for 10 years. What will be her EMI under flat rate system?

2025: 22 May Shift 1

The term of the perpetuity is

2026: 22 May Shift 1

What amount is received at the end of every 6 months forever, if ₹72,000 kept in a bank earns 8% per annum compounded half-yearly?

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