A function f: R arrow \x R: -1 < x < 1\ is defined as f(x) = x/1+|x|, then f is: Option 1: neither one-one nor onto Option 2: one-one only Option 3: onto only Option 4: both one-one and onto

The answer is 'both one-one and onto'. View full solution:

Algebra > Relations & Functions

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A function $f: \mathbb{R} \rightarrow \{x \in \mathbb{R}: -1 < x < 1\}$ is defined as $f(x) = \frac{x}{1+|x|}$, then $f$ is:

neither one-one nor onto

one-one only

onto only

both one-one and onto

✅ Correct Option: 4

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