Distance of the point (2, 4, -1) from the line 10+2x/2 = y+3/4 = 6-z/9 is Option 1: sqrt(14) units Option 2: 13 units Option 3: 7 units Option 4: sqrt(7) units

The answer is '7 units'. View full solution:

Geometry > 3D Geometry

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Distance of the point $(2, 4, -1)$ from the line $\frac{10+2x}{2} = \frac{y+3}{4} = \frac{6-z}{9}$ is

$\sqrt{14}$ units

13 units

7 units

$\sqrt{7}$ units

✅ Correct Option: 3

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Distance of the point $(2, 4, -1)$ from the line $\frac{10+2x}{2} = \frac{y+3}{4} = \frac{6-z}{9}$ is

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