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If a fair coin is tossed 10 times, then the probability of getting all heads or all tails, is :

Solution

✅ Correct Option: 4

P(all heads) =1210= \frac{1}{2^{10}}. P(all tails) =1210= \frac{1}{2^{10}}. These are mutually exclusive, so P(all heads or all tails) =2210=129= \frac{2}{2^{10}} = \frac{1}{2^9}.

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