Let X denotes the number of doublets obtained in 3 throws of a pair of dice. Match **List-I** with **List-II** | List-I | List-II | |---|---| | (A) P(X = 0) | (I) 1/216 | | (B) P(X = 1) | (II) 15/216 | | (C) P(X = 2) | (III) 75/216 | | (D) P(X = 3) | (IV) 125/216 | Choose the correct answer from the options given below: Option 1: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) Option 2: (A) - (IV), (B) - (II), (C) - (III), (D) - (I) Option 3: (A) - (IV), (B) - (III), (C) - (II), (D) - (I) Option 4: (A) - (I), (B) - (III), (C) - (II), (D) - (IV)

The answer is '(A) - (IV), (B) - (III), (C) - (II), (D) - (I)'. View full solution:

Algebra > Probability

Medium

common

Let X denotes the number of doublets obtained in 3 throws of a pair of dice. Match List-I with List-II | List-I | List-II | |---|---| | (A) $P(X = 0)$ | (I) $\frac{1}{216}$ | | (B) $P(X = 1)$ | (II) $\frac{15}{216}$ | | (C) $P(X = 2)$ | (III) $\frac{75}{216}$ | | (D) $P(X = 3)$ | (IV) $\frac{125}{216}$ | Choose the correct answer from the options given below:

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (IV), (B) - (II), (C) - (III), (D) - (I)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (I), (B) - (III), (C) - (II), (D) - (IV)

✅ Correct Option: 3

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