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Let us consider vector a⃗=(clog⁡2x)i^−6j^+3k^\vec{a} = (c\log_2 x)\hat{i} - 6\hat{j} + 3\hat{k} and b⃗=(log⁡2x)i^+2j^+(2clog⁡2x)k^\vec{b} = (\log_2 x)\hat{i} + 2\hat{j} + (2c\log_2 x)\hat{k}, then which of following statements are TRUE?

(Where x∈Rx \in \mathbb{R} (set of real numbers))

(A) Vector a⃗\vec{a} and b⃗\vec{b} make obtuse angle for any x∈(0,∞)x \in (0,\infty) if c∈(−1,0)c \in (-1,0)

(B) Vector a⃗\vec{a} and b⃗\vec{b} makes obtuse angle for any x∈Rx \in \mathbb{R} if c>0c > 0

(C) Vector a⃗\vec{a} and b⃗\vec{b} makes obtuse angle for any x∈(0,∞)x \in (0,\infty) if c∈(−43,−1]c \in \left(-\frac{4}{3}, -1\right]

(D) Vectors a⃗\vec{a} and b⃗\vec{b} makes obtuse angle for x∈Rx \in \mathbb{R} if c∈(1,2)c \in (1,2)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

Put t=log⁡2xt=\log_2x, which ranges over all reals for x>0x>0. Then a⃗⋅b⃗=ct2+6ct−12\vec a\cdot\vec b=ct^2+6ct-12, and an obtuse angle for every tt needs this to stay negative. That requires c<0c<0 with discriminant 36c2+48c<036c^2+48c<0, i.e. −43<c<0-\frac43<c<0 (with c=0c=0 also working). So (A) and (C) hold, while positive cc in (B) and (D) fails.

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