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The position vector of a point R which divides the line joining two points P and Q whose position vectors are i^+2j^−k^\hat{i} + 2\hat{j} - \hat{k} and −i^+j^+k^-\hat{i} + \hat{j} + \hat{k} respectively in the ratio 2 : 1 externally is :

Solution

✅ Correct Option: 2

External division formula: R⃗=mQ⃗−nP⃗m−n\vec{R}=\frac{m\vec{Q}-n\vec{P}}{m-n} with m:n=2:1m:n=2:1.

R⃗=2(−i^+j^+k^)−(i^+2j^−k^)1=−3i^+0j^+3k^=−3i^+3k^\vec{R}=\frac{2(-\hat{i}+\hat{j}+\hat{k})-(\hat{i}+2\hat{j}-\hat{k})}{1}=-3\hat{i}+0\hat{j}+3\hat{k}=-3\hat{i}+3\hat{k}.

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