Solution of differential equation dy/dx = 1+x^2/1+y^2 is Option 1: x^3 - y^3 + 3(x+y) + C = 0 : where C is an arbitrary constant Option 2: x^3 + y^3 + 3(x-y) + C = 0: where C is an arbitrary constant Option 3: x^3 - y^3 + 3(x-y) + C = 0: where C is an arbitrary constant Option 4: x^3 + y^3 + 3(x+y) + C = 0: where C is an arbitrary constant

The answer is 'x^3 - y^3 + 3(x-y) + C = 0: where C is an arbitrary constant'. View full solution:

CUET Mathematics - Solution of differential equation dy/dx = 1+x^2/1+y^2 is | PYQs + Solutions

CUET Mathematics 2026 21st May Shift 1

Calculus

Easy

common

$x^3 - y^3 + 3(x+y) + C = 0$ : where $C$ is an arbitrary constant

$x^3 + y^3 + 3(x-y) + C = 0$ : where $C$ is an arbitrary constant

$x^3 - y^3 + 3(x-y) + C = 0$ : where $C$ is an arbitrary constant

$x^3 + y^3 + 3(x+y) + C = 0$ : where $C$ is an arbitrary constant

✅ Correct Option: 3

Related questions:

18th May Shift 1

Match List-I with List-II

List-I Differential equation	List-II Order and degree
(A) $\frac{d^4y}{dx^4} + \sin\left(\frac{d^3y}{dx^3}\right) = 0$	(I) order = 2, degree = 1
(B) $\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} = 0$	(II) order = 3, degree = 1
(C) $\frac{d^3y}{dx^3} + y^2 + \frac{dy}{dx} = 0$	(III) order = 2, degree = 2
(D) $3y\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^4 = 0$	(IV) order = 4, degree not defined

Choose the correct answer from the options given below:

23 May Shift 3

Which of the following differential equation represents the family of circles touching the x-axis at the origin ?

29th May Shift 1

Match List-I with List-II

List-I (Differential Equation)	List-II (Degree)
(A) $\left(\dfrac{dy}{dx}\right)^3+\left(\dfrac{d^2y}{dx^2}\right)^2=0$	(I) Not defined
(B) $\left(\dfrac{d^2y}{dx^2}\right)^3+\left(\dfrac{dy}{dx}\right)^2+1=0$	(II) 2
(C) $\sqrt{1+\dfrac{d^2y}{dx^2}}=\dfrac{dy}{dx}+x$	(III) 1
(D) $\dfrac{d^2y}{dx^2}+e^{\frac{dy}{dx}}=0$	(IV) 3

Choose the correct answer from the options given below: