CUET Mathematics 2026 21st May Shift 1 PYQs

$\displaystyle\int_{-\pi/3}^{\pi/3} 2x^5\cos^4 x\, dx$ equals

The integral I = $\int e^x\left(\frac{x - 1}{3x^2}\right) dx$ is equal to

$\int\frac{\tan^5\sqrt{x}.\sec^2\sqrt{x}}{\sqrt{x}}dx$ is equal to: