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If A is a square matrix [5−5−55]\begin{bmatrix} 5 & -5 \\ -5 & 5 \end{bmatrix} such that A2=p AA^2 = p\,A, then the value of p is,

Solution

✅ Correct Option: 3

Computing A2A^2 gives [50−50−5050]\begin{bmatrix}50&-50\\-50&50\end{bmatrix}, which is 1010 times AA. Hence p=10p=10.

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