Match **List - I** with **List - II**. | | List - I | | List - II | |---|---|---|---| | (A) | Area of triangle with adjacent sides a and b | (I) | a x b | | (B) | Area of parallelogram with adjacent side a x b | (II) | 1/2|a x b| | | (C) | (a - b) x (a + b) | (III) | |a x b| | | (D) | |a||b|, where symbols have their usual meaning | (IV) | 2(a x b) | Choose the **correct** answer from the options given below :

Question

Option 1: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Option 2: (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Option 3: (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Option 4: (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

AfterBoards · Accepted Answer

The answer is '(A)-(II), (B)-(III), (C)-(IV), (D)-(I)'. View full solution:

List-I	List-II
(A) The vectors $\lambda\hat{i}$ $+ \hat{j} + 2\hat{k}$ and $\vec{i} + \lambda\hat{j} + \hat{k}$ are perpendicular if λ is equal to	(I) 1
(B) The vectors $3\hat{i} + 6\hat{j} - \hat{k}$ and $2\hat{i} + 4\hat{j} - \lambda\hat{k}$ are collinear if λ is equal to	(II) -1
(C) The number of vectors of unit-length which are perpendicular to both the vectors $\vec{a}$ = $\hat{i} + \hat{j} + 2\hat{k}$ and $\vec{b}$ = $3\hat{i} - \hat{j} + 5\hat{k}$ is	(III) 2/3
(D) If $\lvert \vec{a} \rvert = 1$ and $\vec{a} + \vec{b} = \vec{0}$ , then $\lvert \vec{b} \rvert$ is equal to	(IV) 2

CUET Mathematics 2023 22 May Shift 3 PYQs

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