CUET MathematicsAlgebra > Mediumcore16i^+26j^+16k^\frac{1}{\sqrt{6}} \hat{i}+\frac{2}{\sqrt{6}} \hat{\mathrm{j}}+\frac{1}{\sqrt{6}} \hat{\mathrm{k}}61i^+62j^+61k^−16i^+16j^−16k^-\frac{1}{\sqrt{6}} \hat{\mathrm{i}}+\frac{1}{\sqrt{6}} \hat{\mathrm{j}}-\frac{1}{\sqrt{6}} \hat{\mathrm{k}}−61i^+61j^−61k^−16i^+26j^+26k^-\frac{1}{\sqrt{6}} \hat{\mathrm{i}}+\frac{2}{\sqrt{6}} \hat{\mathrm{j}}+\frac{2}{\sqrt{6}} \hat{\mathrm{k}}−61i^+62j^+62k^−16i^+26j^−16k^-\frac{1}{\sqrt{6}} \hat{\mathrm{i}}+\frac{2}{\sqrt{6}} \hat{\mathrm{j}}-\frac{1}{\sqrt{6}} \hat{\mathrm{k}}−61i^+62j^−61k^✅ Correct Option: 4Related questions:3 June Shift 1Let a⃗=i^+4j^+2k^\vec{a} = \hat{i} + 4\hat{j} + 2\hat{k}a=i^+4j^+2k^, b⃗=3i^−2j^+7k^\vec{b} = 3\hat{i} - 2\hat{j} + 7\hat{k}b=3i^−2j^+7k^ and c⃗=2i^+j^+4k^\vec{c} = 2\hat{i} + \hat{j} + 4\hat{k}c=2i^+j^+4k^. A vector d⃗\vec{d}d which is perpendicular to both a⃗\vec{a}a and b⃗\vec{b}b, and c⃗⋅d⃗=14\vec{c} \cdot \vec{d} = 14c⋅d=14, is:30 May Shift 1Let a⃗=2i^−j^b⃗−4j^+k and c⃗=i^+2k^\vec{a} = 2\hat{i} - \hat{j} \vec{b} - 4\hat{j} + k\,\text{and}\,\vec{c} = \hat{i} + 2\hat{k}a=2i^−j^b−4j^+kandc=i^+2k^. If d⃗\vec{d}d is a vector perpendicular to both a⃗\vec{a}a and b⃗\vec{b}b such that c⃗⋅d⃗=34\vec{c} \cdot \vec{d} = 34c⋅d=34, then ∣d⃗∣|\vec{d}|∣d∣ is equal to2 June Shift 1Which of the following statements are true? (A) If r⃗=xi^+yj^+zk^\vec{r} = x\hat{i} + y\hat{j} + z\hat{k}r=xi^+yj^+zk^, then x,y,zx, y, zx,y,z are called direction ratios of r⃗\vec{r}r. (B) For any two vectors a⃗\vec{a}a and b⃗\vec{b}b, a⃗+b⃗=b⃗+a⃗\vec{a} + \vec{b} = \vec{b} + \vec{a}a+b=b+a (C) a⃗⊥b⃗\vec{a} \perp \vec{b}a⊥b if and only if a⃗×b⃗=0⃗\vec{a} \times \vec{b} = \vec{0}a×b=0 (D) Projection of b⃗\vec{b}b on a⃗\vec{a}a is a⃗⋅b⃗∣a⃗∣2\frac{\vec{a} \cdot \vec{b}}{|\vec{a}|^2}∣a∣2a⋅b Choose the correct answer from the options given below: