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The function f(x)=sin⁡x+cos⁡xf(x) = \sin x + \cos x; 0≤x≤2π0 \leq x \leq 2\pi is

(A) Increasing in (0,π4)\left(0, \frac{\pi}{4}\right)

(B) Decreasing in (0,π)(0, \pi)

(C) Increasing in (5π4,2π)\left(\frac{5\pi}{4}, 2\pi\right)

(D) Decreasing in (π4,5π4)\left(\frac{\pi}{4}, \frac{5\pi}{4}\right)

(E) Neither increasing Nor decreasing in (0,π4)\left(0, \frac{\pi}{4}\right)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

f′(x)=cos⁡x−sin⁡xf'(x)=\cos x-\sin x, which is positive on (0,π4)\left(0,\frac{\pi}{4}\right) and (5π4,2π)\left(\frac{5\pi}{4},2\pi\right) and negative on (π4,5π4)\left(\frac{\pi}{4},\frac{5\pi}{4}\right). So (A), (C) and (D) are correct, while (B) fails because ff increases on part of (0,π)(0,\pi), and (E) contradicts (A).

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