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If y=log⁡x(x2+1).log⁡(x2+1)xy = \log_x(x^2+1).\log_{(x^2+1)} x, then dydx\frac{dy}{dx} is

Solution

✅ Correct Option: 4

Change of base gives log⁡x(x2+1)⋅log⁡(x2+1)x=log⁡(x2+1)log⁡x⋅log⁡xlog⁡(x2+1)=1\log_x(x^2+1)\cdot\log_{(x^2+1)}x=\frac{\log(x^2+1)}{\log x}\cdot\frac{\log x}{\log(x^2+1)}=1. Since yy is the constant 1, dydx=0\frac{dy}{dx}=0.

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