The maximum value of $z = 3x + 4y$ subject to the constraints

$x + y \geq 2, 2x + 3y \leq 6, x \geq 0, y \geq 0$ is

Consider a L.P.P, Maximize $Z = 3x + 5y$ subject to constraints $2x + 6y ≤ 6$, $x - y ≥ 0$, $x ≥ 0$, $y ≥ 0$. Then which of the following are true?

(A) The feasible region of L.P.P is bounded region

(B) The corner points of the feasible region are (0, 0), (2, 2), (0, 1)

(C) Maximum value of Z is 9

(D) Point (1, 3) lies in the feasible region

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The maximum value of $z = 4x + 3y$, if the feasible region for an LPP is as shown below is:

If the corner points of bounded feasible region for an LPP are (0,2) (3,0) (6,0) (6,8) and (0, 5) then the minimum value of the objective function f=4x+6y occur at

The number of corner points of the feasible region of an LPP determined by the constraints $x - y \geq 0$, $2y \leq x + 2, x \geq 0, y \geq 0$ is

About linear programming problem (LPP), which of the following statements are correct?

(A) In a LPP, the linear inequalities or restrictions on the variables are called linear constraints.

(B) If the feasible region for an LPP is unbounded, then the maximum or minimum value of the objective function $Z = ax + by$ never exists.

(C) The feasible region for an LPP is always convex.

(D) The common region determined by all the linear constraints of an LPP is called the feasible region.

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The corner points of the feasible region determined by the following system of linear inequalities :

$2x + y \leq 10$, $x + 3y \leq 15$, $x, y \geq 0$ are (0, 0), (5, 0), (3, 4) and (0, 5). Let $z = px + qy$, where $p, q > 0$ condition on p and q so that maximum of z occurs at both (3, 4) and (0, 5) is :