CUET Mathematics 2026 21st May Shift 1 PYQs

$\frac{x^3}{3} + 2^x \log 2 + 4x + C$: where $C$ is an arbitrary constant

$\frac{x^3}{3} + \frac{2^x}{\log 2} + 4x + C$: where $C$ is an arbitrary constant

$\frac{x^3}{3} + 2^x \log 2 + C$: where $C$ is an arbitrary constant

$\frac{x^3}{3} + \frac{2^x}{\log 2} + C$: where $C$ is an arbitrary constant