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Match List-I with List-II

List-I (Differential Equation)List-II (Degree)
(A) 2(y′′)2+3y=62(y'')^2 + 3y = 6(I) 4
(B) 2y+5(y′)4=72y + 5(y')^4 = 7(II) 1
(C) log⁡x+(y′′)3=ex\log x + (y'')^3 = e^x(III) 2
(D) 1−2y′=5(y′′)14\sqrt{1-2y'} = 5(y'')^{\frac{1}{4}}(IV) 3

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Degree is the power of the highest-order derivative once the equation is polynomial in derivatives. (A) (y′′)2(y'')^2 gives degree 2 (III). (B) highest order is y′y' with power 4, degree 4 (I). (C) (y′′)3(y'')^3 gives degree 3 (IV). (D) squaring twice gives (1−2y′)2=625 y′′(1-2y')^2=625\,y'', so degree 1 (II).

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