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A sample of size 9 from a normal population with sample mean Xˉ=15.8\bar{X} = 15.8 and population estimated standard deviation σ=3.21\sigma = 3.21, then 99% confidence interval for population mean is : (Use:t8(0.01)=3.335)(Use: t_8(0.01) = 3.335)

Solution

✅ Correct Option: 2

The interval is Xˉ±tσn=15.8±3.335×3.213=15.8±3.335×1.07≈15.8±3.57\bar X\pm t\frac{\sigma}{\sqrt n}=15.8\pm3.335\times\frac{3.21}{3}=15.8\pm3.335\times1.07\approx15.8\pm3.57. This gives approximately [12.23, 19.37][12.23,\,19.37].

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