The integral I = (1+ x)^3/x dx equals: Option 1: 1/x^4 + C, Where C is an arbitrary constant Option 2: (1+ x)^4/4 + C, Where C is an arbitrary constant Option 3: x/x^3 + C, Where C is an arbitrary constant Option 4: (1+ x)^3/3 + C, Where C is an arbitrary constant

The answer is '(1+ x)^4/4 + C, Where C is an arbitrary constant'. View full solution:

CUET Mathematics - The integral I = (1+ x)^3/x dx equals: | PYQs + Solutions

CUET Mathematics 2026 21st May Shift 1

Calculus

Easy

applied

$\frac{1}{x^4} + C$ , Where $C$ is an arbitrary constant

$\frac{(1+\log x)^4}{4} + C$ , Where $C$ is an arbitrary constant

$\frac{\log x}{x^3} + C$ , Where $C$ is an arbitrary constant

$\frac{(1+\log x)^3}{3} + C$ , Where $C$ is an arbitrary constant

✅ Correct Option: 2

List-I	List-II
(A) The value of $\int_{0}^{4} \vert x\vert \, dx$ is	(I) 3
(B) The value of $\int_{-2}^{2} \vert x\vert \, dx$ is	(II) -1
(C) The value of $\int_{0}^{3} [x] \, dx$ is	(III) 8
(D) The value of $\int_{-1}^{1} [x] \, dx$ is	(IV) 4