Algebra

Probability

Medium

core

A pair of dice is thrown. If the two numbers appearing on them are different then the probability that the sum of the number is 6, is.

$\frac{1}{5}$

$\frac{1}{6}$

$\frac{1}{15}$

$\frac{2}{15}$

✅ Correct Option: 4

Conditioning on the two faces being different leaves $36-6=30$ equally likely outcomes. Sum 6 with distinct faces occurs as $(1,5),(5,1),(2,4),(4,2)$ , i.e. 4 cases, since $(3,3)$ is excluded. Probability $=\frac{4}{30}=\frac{2}{15}$ .

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A pair of dice is thrown. If the two numbers appearing on them are different then the probability that the sum of the number is 6, is.

Solution

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