Algebra

Probability

Easy

applied

Two dice are thrown then the probability of the sum of numbers appearing to be prime is :

$\frac{15}{36}$

$\frac{20}{36}$

$\frac{13}{36}$

$\frac{14}{36}$

✅ Correct Option: 1

Prime sums are 2, 3, 5, 7 and 11, occurring in 1, 2, 4, 6 and 2 ways respectively. That is 15 favourable outcomes out of 36, so the probability is $\frac{15}{36}$ .

2026: 30 May Shift 2

A man is known to speak truth 4 out of 5 times. A coin is tossed. He reports that a head appears. The probability that actually there was a head, is

2026: 18 May Shift 2

If $P(A) = 0.4$ , $P(B) = X$ and $P(\bar{A} \cap \bar{B}) = 0.4$ , where A and B are independent event, then the value of X is:

2025: 13 May Shift 2

The probability of not getting 53 Sundays in a leap year is

2025: 15 May Shift 2

If a random variable $X$ has the following probability distribution:

X	0	1	2	3	4
P(X)	k	2k	3k	k²	6k²

, then

Match List-I with List-II

List-I	List-II
(A) k	(I) 3/7
(B) $P(X < 2)$	(II) 6/49
(C) $P(X > 3)$	(III) 1/7
(D) $P(2 \leq X \leq 3)$	(IV) 22/49

Choose the correct answer from the options given below:

2025: 3 June Shift 2

The binomial distribution for which the mean is 5 and variance 4, is

2025: 15 May Shift 1

The probability of a man hitting a target is 1/2. How many times must he fire so that the probability of hitting the target at least once is more than 90%?

Two dice are thrown then the probability of the sum of numbers appearing to be prime is :

Solution

Related questions:

Keyboard Shortcuts

CUET Mathematics Past Year Questions (Topic-Wise)