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∫x3(x3+4x2+7) dx\displaystyle\int \sqrt[3]{x}(x^3+4x^2+7)\,dx is equal to-

Solution

✅ Correct Option: 2

Expand the integrand as x10/3+4x7/3+7x1/3x^{10/3}+4x^{7/3}+7x^{1/3}.

Integrating term by term gives 313x13/3+65x10/3+214x4/3+c\dfrac{3}{13}x^{13/3}+\dfrac{6}{5}x^{10/3}+\dfrac{21}{4}x^{4/3}+c.

Taking 33 common gives 3[113x13/3+25x10/3+74x4/3]+c3\left[\dfrac{1}{13}x^{13/3}+\dfrac{2}{5}x^{10/3}+\dfrac{7}{4}x^{4/3}\right]+c.

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