CUET Mathematics 2026 26th May Shift 2 PYQs

$x^3 + \dfrac{(x^2-1)^{3/2}}{3} + C$,where $C$ is an arbitrary constant.

$\dfrac{x^4}{3} + \dfrac{(x^2-1)^{3/2}}{3} + C$,where $C$ is an arbitrary constant.

$\dfrac{x^3}{3} - \dfrac{(x^2-1)^{3/2}}{3} + C$,where $C$ is an arbitrary constant.

$\dfrac{x^3}{3} + \dfrac{(x^2-1)^{3/2}}{3} + C$,where $C$ is an arbitrary constant.