The particular solution of the differential equation (dy/dx)=3x+4y, given that y=0, when x=0 is: Option 1: 3e^-3x+4e^4y=12 Option 2: 4e^-3x+3e^4y=7 Option 3: 4e^3x+3e^-4y=7 Option 4: 3e^3x+4e^-4y=12

The answer is '4e^3x+3e^-4y=7'. View full solution:

CUET Mathematics - The particular solution of the differential equation (dy/dx)=3x+4y, given that y=0, when x=0 is: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 1

Calculus

Medium

applied

$3e^{-3x}+4e^{4y}=12$

$4e^{-3x}+3e^{4y}=7$

$4e^{3x}+3e^{-4y}=7$

$3e^{3x}+4e^{-4y}=12$

✅ Correct Option: 3

Related questions:

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Match the LIST-I with LIST-II

LIST-I (Differential Equation)		LIST-II (Degree of Differential Equation)
A. $\dfrac{d^3y}{dx^3} + \left(\dfrac{d^2y}{dx^2}\right)^2 - \dfrac{dy}{dx} + y = 0$		I. 2
B. $\dfrac{dy}{dx} + \left(\dfrac{d^2y}{dx^2}\right)^4 + 2\left(\dfrac{d^3y}{dx^3}\right)^3 = 0$		II. 4
C. $\left(\dfrac{d^3y}{dx^3}\right)^2 + \left(\dfrac{d^2y}{dx^2}\right)^4 - y = 0$		III. 1
D. $\left(\dfrac{d^2y}{dx^2}\right)^4 + \left(\dfrac{dy}{dx}\right)^3 + y = 0$		IV. 3

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