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If A+B=[7025]A+B = \begin{bmatrix}7 & 0\\2 & 5\end{bmatrix} and A−B=[3003]A-B = \begin{bmatrix}3 & 0\\0 & 3\end{bmatrix}, then

Solution

✅ Correct Option: 1

Adding the two matrices gives 2A=[10028]2A=\begin{bmatrix}10&0\\2&8\end{bmatrix}, so A=[5014]A=\begin{bmatrix}5&0\\1&4\end{bmatrix}. Subtracting gives 2B=[4022]2B=\begin{bmatrix}4&0\\2&2\end{bmatrix}, so B=[2011]B=\begin{bmatrix}2&0\\1&1\end{bmatrix}.

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