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For a square matrix AA of order 3, if ∣A∣=−3\lvert A\rvert = -3, then ∣4 adjA∣\lvert 4\,adj A\rvert is equal to

Solution

✅ Correct Option: 1

For order n=3n=3, ∣adj A∣=∣A∣n−1=(−3)2=9|\mathrm{adj}\,A| = |A|^{n-1} = (-3)^2 = 9.

Scalar multiple: ∣kB∣=kn∣B∣|kB| = k^n|B|, so ∣4 adj A∣=43×9=64×9=576|4\,\mathrm{adj}\,A| = 4^3 \times 9 = 64 \times 9 = 576.

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