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The general solution of the differential equation x dx=(x2+1) dyx\,dx = (x^2+1)\,dy is (where C is an arbitrary constant)

Solution

✅ Correct Option: 2

Separating variables, dy=x dxx2+1dy=\frac{x\,dx}{x^2+1}. Put t=x2+1t=x^2+1, dt=2x dxdt=2x\,dx, so the right side is 12∫dtt\frac12\int\frac{dt}{t}. Hence y=12log⁡e∣x2+1∣+Cy=\frac12\log_e|x^2+1|+C.

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