If y = ( x), then d^2y/dx^2 is equal to: (Consider _e x = x) Option 1: 1/x x Option 2: -(1+ x)/(x x)^2 Option 3: x/ x Option 4: (1+ x)/x x

The answer is '-(1+ x)/(x x)^2'. View full solution:

CUET Mathematics - If y = ( x), then d^2y/dx^2 is equal to: (Consider _e x = x) | PYQs + Solutions

CUET Mathematics 2026 29th May Shift 2

Calculus

Medium

common

$\frac{1}{x\log x}$

$-\frac{(1+\log x)}{(x\log x)^2}$

$\frac{x}{\log x}$

$\frac{(1+\log x)}{x\log x}$

✅ Correct Option: 2

Related questions:

29 May Shift 2

If $x = a\sin 2t(1 + \cos 2t)$ and $y = b\cos 2t(1 - \cos 2t)$ , then $(\frac{dy}{dx})_{\text{at } x=\frac{\pi}{4}}$ is equal to

19th May Shift 1

Match List-I with List-II

List-I	List-II
(A) $f(x) = \begin{cases} x^{10}-1 & , x \leq 1 \\ x^2 & , x > 1 \end{cases}$	(I) is continuous at all points of domain
(B) $g(x) = [x]$ , $[x]$ denotes the greatest integer function	(II) is continuous at $x = 0$
(C) $h(x) = \begin{cases} \dfrac{\sin x}{x} & , x < 0 \\ x+1 & , x \geq 0 \end{cases}$	(III) is discontinuous at $x = -2$
(D) $p(x) = \begin{cases} \dfrac{x}{\left\vert x \right\vert} & , x < 0 \\ -1 & , x \geq 0 \end{cases}$	(IV) is discontinuous at $x = 1$

Choose the correct answer from the options given below:

16 May Shift 1

The equation of the tangent to the curve $\mathrm{x}^{\frac{5}{2}}+\mathrm{y}^{\frac{5}{2}}=33$ at the point $(1,4)$ is :