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A box contains 3 red and 2 black balls and another box contains 2 red and 4 black balls. One box chosen at random. From the selected box one ball is drawn. The probability of getting a red ball is

Solution

✅ Correct Option: 3

Each box is equally likely. So P=12⋅35+12⋅26=310+16=9+530=715P=\frac12\cdot\frac35+\frac12\cdot\frac26=\frac{3}{10}+\frac16=\frac{9+5}{30}=\frac{7}{15}.

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