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If A and B are square matrices of order 3×3 such that |A|=7 and |B|=6, then |B adj A| =

Solution

✅ Correct Option: 4

∣adjA∣=∣A∣n−1=72=49|\text{adj}A|=|A|^{n-1}=7^2=49 for order 3. Then ∣B adjA∣=∣B∣∣adjA∣=6×49=294|B\,\text{adj}A|=|B||\text{adj}A|=6\times49=294.

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