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The area of the region bounded by the curve x2=4yx^2=4y, the line x=4y−2x=4y-2 and x-axis is

Solution

✅ Correct Option: 3

The line y=x+24y=\frac{x+2}{4} meets the x-axis at x=−2x=-2 and meets y=x24y=\frac{x^2}{4} at x=−1x=-1 and x=2x=2; the parabola meets the x-axis at x=0x=0. The bounded region gives area =∫−2−1x+24dx+∫−10x24dx=18+112=524=\int_{-2}^{-1}\frac{x+2}{4}dx+\int_{-1}^{0}\frac{x^2}{4}dx=\frac18+\frac1{12}=\frac{5}{24}.

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