Skip to main contentSkip to solution

Match the LIST-I with LIST-II (Consider N and R as set of natural numbers and set of real numbers respectively)

LIST-I
Function
LIST-II
A.f:N→N,f(x)=x2f: N \to N, f(x) = x^2 isI.Neither one-one nor onto
B.f:R→R,f(x)=3−2xf: R \to R, f(x) = 3 - 2x isII.one-one but not onto
C.f:R→R,f(x)=x2f: R \to R, f(x) = x^2 isIII.onto but not one-one
D.f:{−1,1}→{1},f(x)=∣x∣f: \{-1,1\} \to \{1\}, f(x) = \vert x \vert isIV.one-one and onto

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

On NN, x2x^2 is injective but misses 2, 3, so one-one not onto (A-II). 3−2x3-2x on RR is a non-constant linear map, hence bijective (B-IV). On RR, x2x^2 is neither, since f(1)=f(−1)f(1)=f(-1) and negatives are unattained (C-I). ∣x∣|x| on {−1,1}→{1}\{-1,1\}\to\{1\} covers the codomain but is not injective (D-III).

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question