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If 77≡x(mod 4)77 \equiv x(mod\ 4), then the least positive value of xx is :

Solution

✅ Correct Option: 3

Dividing, 77=4×19+177=4\times19+1, so the remainder is 1. Hence 77≡1(mod4)77\equiv1\pmod4 and the least positive value of xx is 1.

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