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The marginal cost (MC) of producing x units of an item in a factory is given by MC=0.006x2−0.001x+4MC=0.006x^2-0.001x+4.

If the fixed cost is ₹1000, then the cost of producing 200 units will be :

Solution

✅ Correct Option: 2

Integrating, C(x)=0.002x3−0.0005x2+4x+kC(x)=0.002x^3-0.0005x^2+4x+k, with k=1000k=1000 as the fixed cost. At x=200x=200: 0.002(8,000,000)=160000.002(8{,}000{,}000)=16000, −0.0005(40,000)=−20-0.0005(40{,}000)=-20, 4(200)=8004(200)=800. Total =16000−20+800+1000=17,780=16000-20+800+1000=17{,}780.

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