If ^6 x^10 x dx = -2a^9 x + b^7 x + c, (where c is an arbitrary constant), then which one of the following is TRUE? Option 1: 18a=7b Option 2: 18a+7b=0 Option 3: 7a=18b Option 4: 7a+18b=0

The answer is '18a+7b=0'. View full solution:

CUET Mathematics - If ^6 x^10 x dx = -2a^9 x + b^7 x + c, (where c is an arbitrary constant), then which one of the following is TRUE? | PYQs + Solutions

CUET Mathematics 2026 29th May Shift 2

Calculus

Hard

core

18a=7b

18a+7b=0

7a=18b

7a+18b=0

✅ Correct Option: 2

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