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If matrix A=[03a−42122b2−1]A=\begin{bmatrix}0&3a&-4\\2&1&2\\2b&2&-1\end{bmatrix} is a symmetric matrix, then the values of aa and bb are

Solution

✅ Correct Option: 3

Symmetry requires aij=ajia_{ij}=a_{ji}. From a12=a21a_{12}=a_{21}: 3a=23a=2, so a=23a=\frac23. From a13=a31a_{13}=a_{31}: −4=2b-4=2b, so b=−2b=-2. The pair a23=a32=2a_{23}=a_{32}=2 is already consistent.

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