If P(B) = 2/5, P(A B) = 3/5, P(A B) = 3/10 then P(A/B) + 2P(B/A) equals Option 1: 20/39 Option 2: 39/20 Option 3: 39/10 Option 4: 10/39

Answer: 39/20. Solution: P(A)=P(A B)+P(A B)-P(B)=35+3/10-25=12. Then P(A/B)=(3/10)/(2/5)=34 and P(B/A)=(3/10)/(1/2)=35. So the sum is 34+65=39/20.

Algebra

Probability

Medium

common

If $P(B) = \frac{2}{5}, P(A \cup B) = \frac{3}{5}, P(A \cap B) = \frac{3}{10}$ then $P(A/B) + 2P(B/A)$ equals

$\frac{20}{39}$

$\frac{39}{20}$

$\frac{39}{10}$

$\frac{10}{39}$

✅ Correct Option: 2

$P(A)=P(A\cup B)+P(A\cap B)-P(B)=\frac35+\frac{3}{10}-\frac25=\frac12$ . Then $P(A/B)=\frac{3/10}{2/5}=\frac34$ and $P(B/A)=\frac{3/10}{1/2}=\frac35$ . So the sum is $\frac34+\frac65=\frac{39}{20}$ .

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P(X)	0.1	k	0.2	2k	0.3	k

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Match the LIST-I with LIST-II

LIST-I		LIST-II
A. $P(X=0)$		I. 1
B. $P(X=1)$		II. $\dfrac{19}{34}$
C. $P(X=2)$		III. $\dfrac{13}{34}$
D. $P(X<3)$		IV. $\dfrac{1}{17}$

Choose the correct answer from the options given below:

If P(B)=25,P(A∪B)=35,P(A∩B)=310P(B) = \frac{2}{5}, P(A \cup B) = \frac{3}{5}, P(A \cap B) = \frac{3}{10}P(B)=52​,P(A∪B)=53​,P(A∩B)=103​ then P(A/B)+2P(B/A)P(A/B) + 2P(B/A)P(A/B)+2P(B/A) equals

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CUET Mathematics Past Year Questions (Topic-Wise)

If $P(B) = \frac{2}{5}, P(A \cup B) = \frac{3}{5}, P(A \cap B) = \frac{3}{10}$ then $P(A/B) + 2P(B/A)$ equals