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Let A=[3−124]A = \begin{bmatrix} 3 & -1 \\ 2 & 4 \end{bmatrix}, then adjoint (A) is:

Solution

✅ Correct Option: 4

For a 2×22\times2 matrix [abcd]\begin{bmatrix} a & b \\ c & d \end{bmatrix}, the adjoint is [d−b−ca]\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}. Hence adj(A)=[41−23]\text{adj}(A) = \begin{bmatrix} 4 & 1 \\ -2 & 3 \end{bmatrix}.

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