Given that [a_ij] is a square matrix of order n. Match the LIST-I with LIST-II | LIST-I | | LIST-II | |---|---|---| | A. | A=[a_ij]; a_ij=cases1, & i=j\0, & i≠ jcases | I. Identity Matrix | | B. | B=[a_ij]; a_ij=cases2i-3j, & i=j\0, & i≠ jcases | II. Diagonal Matrix | | C. | C=[a_ij]; a_ij=casesk, & i=j\0, & i≠ jcases | III. Scalar Matrix | | D. | D=[a_ij]; a_ij=cases2i-3j, & i≤ j\0, & ijcases | IV. Upper Triangular Matrix | Choose the correct answer from the options given below:

Question

Given that [a_ij] is a square matrix of order n. Match the LIST-I with LIST-II | LIST-I | | LIST-II | |---|---|---| | A. | A=[a_ij]; a_ij=cases1, & i=j\0, & i≠ jcases | I. Identity Matrix | | B. | B=[a_ij]; a_ij=cases2i-3j, & i=j\0, & i≠ jcases | II. Diagonal Matrix | | C. | C=[a_ij]; a_ij=casesk, & i=j\0, & i≠ jcases | III. Scalar Matrix | | D. | D=[a_ij]; a_ij=cases2i-3j, & i≤ j\0, & i>jcases | IV. Upper Triangular Matrix | Choose the correct answer from the options given below:

Option 1: A - I, B - II, C - III, D - IV

Option 2: A - I, B - IV, C - II, D - III

Option 3: A - I, B - II, C - IV, D - III

Option 4: A - II, B - III, C - IV, D - I

AfterBoards · Accepted Answer

The answer is 'A - I, B - II, C - III, D - IV'. View full solution:

CUET Mathematics 2026 29th May Shift 2 PYQs

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