The solution to the inequality -12 < (2x-1)/3 < 12 is Option 1: ((-35)/2,37/2) Option 2: [(-35)/2,37/2] Option 3: ((-37)/2,35/2) Option 4: [(-37)/2,35/2]

Answer: ((-35)/2,37/2). Solution: Multiplying by 3, -36<2x-1<36. Adding 1, -35<2x<37, so -35/2<x<37/2. The inequality is strict, so the interval is open.

Algebra

Inequalities

Easy

applied

The solution to the inequality $-12 < \frac{2x-1}{3} < 12$ is

$\left(\frac{-35}{2},\frac{37}{2}\right)$

$\left[\frac{-35}{2},\frac{37}{2}\right]$

$\left(\frac{-37}{2},\frac{35}{2}\right)$

$\left[\frac{-37}{2},\frac{35}{2}\right]$

✅ Correct Option: 1

Multiplying by 3, $-36<2x-1<36$ . Adding 1, $-35<2x<37$ , so $-\frac{35}{2}<x<\frac{37}{2}$ . The inequality is strict, so the interval is open.

2025: 30 May Shift 1

If $\mathbb{Z}$ and $\mathbb{R}$ denote set of integers and set of real numbers respectively, then match List I with List II.

List-I	List-II
(A) $5x - 3 \leq 3x + 1$ , $x \in \mathbb{Z}$	(I) $x \in (-\infty, -3]$
(B) $3x + 17 \leq 2(1 - x)$ , $x \in \mathbb{R}$	(II) $x \in (-\infty, -1)$
(C) $13x + 17 \leq 2(1 - x)$ , $x \in \mathbb{R}$	(III) $\{......, -4, -3, .......,0,1\}$
(D) $\frac{2x + 3}{5} - 2 > \frac{3(x - 2)}{5}$ , $x \in \mathbb{Z}$	(IV) $\{......, -4, -3, -2\}$

Choose the correct answer from the options given below:

2026: 21 May Shift 2

The solution set for the inequality $|5x-3| \le \dfrac{1}{5}$ is:

2025: 21 May Shift 1

The solution set of the inequation $|2x - 3| ≤ 4$ is

2025: 22 May Shift 1

The solution set of the inequation $4x + 3y > 5$ is

2026: 29 May Shift 2

Which of the following shaded regions represents the solution to the inequation $|x|+|y| \leq 1$ ?

2026: 22 May Shift 1

Match List-I with List-II

List-I	List-II
Inequalities	Solution set
(A) If $\left\vert 3 - 5x \right\vert < 7$ , then $x \in$	(I) $\left[-\dfrac{5}{2}, \infty\right)$
(B) If $3x - 7 > 5x - 1$ , then $x \in$	(II) $(-\infty, -3)$
(C) If $\dfrac{x}{3} > \dfrac{x}{2} + 1$ , then $x \in$	(III) $\left(-\dfrac{4}{5}, 2\right)$
(D) If $5x + 4 \leq 7x + 9$ , then $x \in$	(IV) $(-\infty, -6)$

Choose the correct answer from the options given below:

The solution to the inequality −12<2x−13<12-12 < \frac{2x-1}{3} < 12−12<32x−1​<12 is

Solution

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CUET Mathematics Past Year Questions (Topic-Wise)

The solution to the inequality $-12 < \frac{2x-1}{3} < 12$ is