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The area (in square units) of the region bounded by the curve y2=4ax (a>0)y^2 = 4ax\ (a > 0) and the lines y=2a,x=0y = 2a, x = 0 is equal to:

Solution

✅ Correct Option: 4

Integrate with respect to yy using x=y2/(4a)x = y^2/(4a) from y=0y=0 to y=2ay=2a.

Area =∫02ay24ady=14a⋅8a33=2a23= \int_0^{2a} \frac{y^2}{4a}dy = \frac{1}{4a}\cdot\frac{8a^3}{3} = \frac{2a^2}{3}.

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