Let f: R arrow R be defined as f(x) = 10x. Then (Where R is the set of real numbers) Option 1: f is both one-one and onto Option 2: f is onto but not one-one Option 3: f is one-one but not onto Option 4: f is neither one-one nor onto

The answer is 'f is both one-one and onto'. View full solution:

Algebra > Relations & Functions

Medium

core

Let f: $\mathbb{R} \rightarrow \mathbb{R}$ be defined as $f(x) = 10x$. Then (Where $\mathbb{R}$ is the set of real numbers)

f is both one-one and onto

f is onto but not one-one

f is one-one but not onto

f is neither one-one nor onto

✅ Correct Option: 1

Related questions:

2025: 21 May Shift 2

A relation $f: N \rightarrow N$ be defined by $f(x) = x^2$ , $x \in N$ (Set of Natural numbers). Then $f(x)$ is

2026: 29th May Shift 2

Let S be the set of all real numbers and let R be a relation on S, defined by $aRb \Leftrightarrow |a-b| \leq 1$ . Then, R is

2026: 30th May Shift 1

The relation R in the set of real numbers, defined as R = {(a, b): 1 + ab > 0}, is:

2026: 22nd May Shift 2

The relation R on the set A = {1, 2, 3} defined by R = {(1,1), (2,2), (3,3), (1,3), (2,3), (1,2)} is

2025: 22 May Shift 2

The graph given below represents which of the following function?

2026: 22nd May Shift 1

Let X be a non empty set and S be the collection of all subsets of X. A relation R in S is defined by $R=\{(A,B): A\subseteq B\}$ , where $X\subseteq Y$ means $X$ is proper subset of $Y$ . Then R is:

Let f: $\mathbb{R} \rightarrow \mathbb{R}$ be defined as $f(x) = 10x$. Then (Where $\mathbb{R}$ is the set of real numbers)

Keyboard Shortcuts