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Let f: R→R\mathbb{R} \rightarrow \mathbb{R} be defined as f(x)=10xf(x) = 10x. Then (Where R\mathbb{R} is the set of real numbers)

Solution

✅ Correct Option: 1

To determine the properties of f(x)=10xf(x) = 10x, we need to check if the function is one-one (injective) and onto (surjective).


A function is one-one if f(x1)=f(x2)f(x_1) = f(x_2) implies x1=x2x_1 = x_2.

Suppose f(x1)=f(x2)f(x_1) = f(x_2)

10x1=10x210x_1 = 10x_2

x1=x2x_1 = x_2

Therefore, ff is one-one.


A function f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} is onto if for every real number yy, there exists an xx such that f(x)=yf(x) = y.

Let yy be any real number. Solve for xx:

f(x)=yf(x) = y

10x=y10x = y

x=y10x = \frac{y}{10}

Since yy is a real number, y10\frac{y}{10} is also a real number. Every real number can be achieved as an output.

Therefore, ff is onto.


Since f(x)=10xf(x) = 10x is both one-one and onto, the function is bijective.

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