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If A is a square matrix of order 3 such that ∣A∣=3|A| = 3, then the value of ∣adj A∣+∣adj (adj A)∣|adj\,A| + |adj\,(adj\,A)| is

Solution

✅ Correct Option: 2

For order 33, ∣adj A∣=∣A∣2=9|adj\,A| = |A|^2 = 9.

Also ∣adj(adj A)∣=∣A∣(n−1)2=34=81|adj(adj\,A)| = |A|^{(n-1)^2} = 3^4 = 81.

Adding gives 9+81=909+81 = 90.

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