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∫1−sin⁡xcos⁡2x dx\displaystyle\int \dfrac{1-\sin x}{\cos^2 x}\,dx is equal to:

(where cc is an arbitrary constant)

Solution

✅ Correct Option: 4

Split the integrand as sec⁡2x−sec⁡xtan⁡x\sec^2 x - \sec x\tan x.

Integrating term by term gives tan⁡x−sec⁡x+c\tan x - \sec x + c.

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