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The matrix [001010100]\begin{bmatrix} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{bmatrix} is

Solution

✅ Correct Option: 4

The off-diagonal entries a13a_{13} and a31a_{31} are both 11, so the matrix is unchanged on transposition, i.e. A=ATA = A^T.

It is not diagonal, identity or scalar because non-zero entries appear off the main diagonal.

Hence it is a symmetric matrix.

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