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If a matrix A=[x+332x+15]A = \begin{bmatrix} x+3 & 3 \\ 2x+1 & 5 \end{bmatrix} is singular , then the value of xx will be

Solution

✅ Correct Option: 3

A singular matrix has determinant zero.

So 5(x+3)−3(2x+1)=05(x+3) - 3(2x+1) = 0, giving 5x+15−6x−3=05x+15-6x-3 = 0.

This simplifies to −x+12=0-x+12 = 0, so x=12x = 12.

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