General solution of the differential equation (1+x^2)dy + 2xy dx = x dx is: (where C is an arbitrary constant) Option 1: y(1+x^2) = _e| x| + c Option 2: x(1+y^2) = _e| x| + c Option 3: y(1+x^2) = _e| x| + c Option 4: x(1+y^2) = _e| x| + c

The answer is 'y(1+x^2) = _e| x| + c'. View full solution:

CUET Mathematics - General solution of the differential equation (1+x^2)dy + 2xy dx = x dx is: (where C is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2026 26th May Shift 2

Calculus

Medium

core

$y(1+x^2) = \log_e|\sin x| + c$

$x(1+y^2) = \log_e|\sin x| + c$

$y(1+x^2) = \log_e|\cos x| + c$

$x(1+y^2) = \log_e|\cos x| + c$

✅ Correct Option: 1