Let us denotes R=Periodic payment,i=interest per period per rupee ,n=number of payment,P=pricipal payment

Match the terms in List I with their respective formula in List II.

LIST-I	LIST-II
A. The amount in a sinking fund after $n$ period with payment at end	I. $\dfrac{Pi(1+i)^n}{(1+i)^n - 1}$
B. EMI by using flat rate method	II. $P\left(i + \dfrac{1}{n}\right)$
C. The amount in a sinking fund after $n$ period with payment at beginning	III. $R\left\{\dfrac{(1+i)^n - 1}{i}\right\}$
D. EMI by using reducing balance payment rate method	IV. $R(1+i)\left[\dfrac{(1+i)^n - 1}{i}\right]$

Choose the correct answer from the options given below:

Which of the following are the true?

A. The cost of Rs.7200 , 8% stock at Rs.90 is Rs.6480.

B. The cost of Rs.4500 , 8.5% stock at 4% premium is Rs.4680.

C. The cost of Rs.6400 , 10% stock at 15% discount is Rs.5440.

D. The cost of Rs.7200 , 8% stock at Rs.90 is Rs.5961.60.

Choose the correct answer from the options given below:

Ajesh has set up a sinking fund in order to have ₹ 10,00,000 after 10 years for his son's education. The amount should be set aside at the end of every 6 months into an account paying 5% per annum compounded half yearly is: [given $(1.025)^{20} = 1.6386$]

The price at which the bond is sold to the investors at the time of issue is known as:

Mr. Devendra invested ₹ 8,000 in 7% hundred rupee share at ₹ 80. After a year he sold these share at ₹ 75 each and invested in 18% twenty five-rupee shares at ₹ 41 each. Then his annual income from the second investement is:-

Every year the price of a motorcycle depreciates by Rs. 15000. After 12 years its price has become Rs. 50000. Then its original cost was:

Ram invested Rs.20,000 in a mutual fund in the year 2012. The value of the mutual fund increased to Rs.32,000 in the year 2017, then the compound annual growth rate of his investment is (Given that $(1.6)^{\frac{1}{5}} = 1.098$)