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The solution of the differential equation dydx=x+23−y,(y≠3),y(0)=0\dfrac{dy}{dx} = \dfrac{x+2}{3-y}, (y \neq 3), y(0) = 0

represents

Solution

✅ Correct Option: 1

Separating variables, (3−y)dy=(x+2)dx(3-y)dy = (x+2)dx.

Integrating gives 3y−y22=x22+2x+c3y-\dfrac{y^2}{2} = \dfrac{x^2}{2}+2x+c, i.e. x2+y2+4x−6y+2c=0x^2+y^2+4x-6y+2c = 0.

Since the coefficients of x2x^2 and y2y^2 are equal and there is no xyxy term, this represents a circle.

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